Do...

Nitro · **Joined:** March 8th, 2005, 9:40 pm **Posts:** 63

I am anticipating someone to shoot me down on this :roll:

, and tell me why this is not required, or how a “for” or nested “if” loops can do this, :oops:

but, putting my brave face on… :twisted:

. Remember I am not a programmer! :oops:

How about a “Do” function?

mackavi · **Posted:** September 8th, 2007, 5:43 pm

Run out of bullets :-)

but isn't do part of the while structure that already exists in Opus you just don't need to type the actual word 'do'?

Now if you want to cause an uproar, how about a case statement - nested ifs are just a pain in the behind :-)

Going back to the sunshine.

Mack

Nitro · **Joined:** March 8th, 2005, 9:40 pm **Posts:** 63

Hi Mack,

I already suggested a case (switch) statement in one of my posts, and was told to use nested ifs.

Thanks for the info on "while". I have tried to avoid for and while statements, as I seem to have a mental block against these.

Regards

Neil

Paul · **Posted:** September 8th, 2007, 9:33 pm

Hi Nitro,
I suggested using nested if's -- but when there isn't any choice....

cheers
Paul

Nitro · **Joined:** March 8th, 2005, 9:40 pm **Posts:** 63

Hi Paul,

Please do not misunderstand me. I really appreciate any advice that I get. Even more, I appreciate the fact that you, Mack and others take the time to respond to novices queries.

Thanks for the Tutorial on Loops. My mental block is that I (think) I understand the basics on how to do these, but am lost as to when to do these. My application does not require a lot of loops.

When I think that a loop would result in more efficient coding, suddenly I am at a loss on how to implement this.

Take the following example; I am sure that a loop would have provided more efficient coding.

Code:

Kpress = "0,1,0,2,0,3,0,4,0,5,0,6,0,7,0,8,0,9," 
len = Kpress.length 
Debug.trace(len+"\n") 

var itemdesc = new String(Kpress); 
var myArray = itemdesc.split(","); 

    if(len < 3) 
    var item1 = "00"; 
    var item2 = "00"; 
    var item3 = "00"; 
    var item4 = "00"; 
    var item5 = "00"; 
    var item6 = "00"; 
    var item7 = "00"; 
    var item8 = "00"; 
    var item9 = "00"; 



//1 
    if((len >= 3 )&&(len < 7)){ 
    var item1 = myArray[0]+ myArray[1]; 
    var item2 = "00"; 
    var item3 = "00"; 
    var item4 = "00"; 
    var item5 = "00"; 
    var item6 = "00"; 
    var item7 = "00"; 
    var item8 = "00"; 
    var item9 = "00"; 
    } 
//2 
    if((len >= 7 )&&(len < 11)){ 
    var item1 = myArray[0]+ myArray[1]; 
    var item2 = myArray[2]+ myArray[3]; 
    var item3 = "00"; 
    var item4 = "00"; 
    var item5 = "00"; 
    var item6 = "00"; 
    var item7 = "00"; 
    var item8 = "00"; 
    var item9 = "00"; 
    } 
//3 
   if((len >= 11 )&&(len < 15)){ 
    var item1 = myArray[0]+ myArray[1]; 
    var item2 = myArray[2]+ myArray[3]; 
    var item3 = myArray[4]+ myArray[5]; 
    var item4 = "00"; 
    var item5 = "00"; 
    var item6 = "00"; 
    var item7 = "00"; 
    var item8 = "00"; 
    var item9 = "00"; 
    } 
//etc 
  

Full details on Post: viewtopic.php?t=2828&highlight=

This should probably have looked something like:

Code:

Kpress = "0,1,0,2,0,3,0,4,0,5,0,6,0,7,0,8,0,9," 
len = Kpress.length 
Debug.trace(len+"\n") 

var itemdesc = new String(Kpress); 
var myArray = itemdesc.split(","); 
var itemArray 

If (len < 3) {
  for (i=1;i<=9;i++){ 
      var itemArray[i] = “00”
  }
}

if((len >= 3 )&&(len < 7)){ 
  for (i=2;i<=9;i++){ 
       var itemArray[1] = myArray[0]+ myArray[1];
       var itemArray[i] = “00”
  }
}
if((len >= 7 )&&(len < 11)){ 
  for (i=3;i<=9;i++){ 
       var itemArray[1] = myArray[0]+ myArray[1];
       var itemArray[2] = myArray[1]+ myArray[2];
       var itemArray[i] = “00”
  }
}
//Etc…

I am not sure how to create a blank array.
My guess would be:

Code:

var item = new string()
var itemArray = item.split(“,”) 

I am not sure if this would work, I am just trying to get past my mental block on loops. When I have tried to impliment these in the past, I have had problems.

Thanks again for your input. It really is appreciated!

Regards

Neil

Paul · **Posted:** September 10th, 2007, 12:57 am

Hi Nitro,
Loops will give you shorter coding, but it will not be more efficient.
Looking at your script, I would not try to "improve" it by using loops.
I only use loops if a very regular pattern can be seen, otherwise you end up doing a lot of work for no actual improvement.
Things can get very complicated very quickly.
There is nothing wrong with using the script you wrote as it is.

Paul

mackavi · **Posted:** September 10th, 2007, 5:21 pm

Hi Nitro,

Just a little answer...

To create a new blank array use:

myArray = new Array()

You can specific the number of elements, but it's not necessary.

Mack

Lar_123 · **Posted:** January 29th, 2010, 2:11 am

Quote:

Mackavi: Now if you want to cause an uproar, how about a case statement - nested ifs are just a pain in the behind

Nitro: I already suggested a case (switch) statement in one of my posts, and was told to use nested ifs.

Now see, patience and loyalty pays off. And 'Wishlists' do work. Fine job DW!! This will really be a productivity tool.

I almost 'missed' this in the New Features listing. Now in OpusPro v7 --- code from the 'cycle' sample pub

Code:

   switch(style)
   {
   case "rainbow":
      colour[0]= RGB(224,0,15)
      colour[1]= RGB(255,0,0)
      colour[2]= RGB(255,85,0)
      colour[3]= RGB(255,170,0)
      colour[4]= RGB(255,224,0)
      colour[5]= RGB(255,255,0)
      colour[6]= RGB(224,255,0)
      colour[7]= RGB(170,255,0)
      colour[8]= RGB(85,255,0)
      colour[9]= RGB(0,255,0)
      colour[10]= RGB(10,245,10)
      colour[11]= RGB(0,255,85)
      colour[12]= RGB(0,255,170)
      colour[13]= RGB(0,255,224)
      colour[14]= RGB(0,224,224)
      colour[15]= RGB(0,170,255)
      colour[16]= RGB(0,85,255)
      colour[17]= RGB(0,0,255)
      colour[18]= RGB(10,10,224)
      colour[19]= RGB(85,0,255)
      colour[20]= RGB(100,0,224)
      colour[21]= RGB(150,0,180)
      colour[22]= RGB(170,0,65)
      colour[23]= RGB(196,0,35)
      break;
   case "rainbow quad":
               //**** it continues with similar set of colour values

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