Digital Workshop

IF I have 6 letters
A B C D E F and I want to randomize them in ABC( 3 choices ) multiple choice,but C should be included from the 6 letters.

I hope that I explain it in clear way

Hi OL,
'No' not so clear. Did you mean 'C' is to be 'excluded' (so only 5 letters really). Or 'C' is always to be one of the set of 3 letters ('C' plus 2 random from the other 5)?

Maybe you can provide an example with some context of question plus its multichoice answers. I am GUESSING that you are wanting to generate quizzes by having the one correct answer always included (but not always in position C or with label C). And then populate the wrong answers so that different versions of the test can be made. Is that it?

Hi lar
Yes ,exactly that is.
How could that be done?

Hi Opuslover,

There are all manor of ways of doing this. If you've not already got it - download our free random quiz example from our website.

You can easily change the multi-frame idea to display various combinations of right / wrong answers.

Mack

hi mack
I already had your randomize
but as Lar said . i want one of the choices be included as a must

I random 6 words, then the choices will be only 3
one of these randomize should be included

the simplest way:

the random words are:

boy - school - girl - class - crayon - chair

question1
what is this?(a picture of a chair)
choose a , b or c:
a-school
b- boy
c.( should be chair) but I don't want it always to be c . It could be b or a



if we make it the normal ranmize way . maybe the chair ( which is the answer will not be included).

I hope this time clear.

It was clear first time

The example we have always includes item one as the must. You can simply have X number of false answers from a pool of false answers.

But to do it through scripts, is the same principle. Just fixed variable, the right answer and pool of false answers - probably and array, the draw two false answers from this array and include with the true fixed answer.

Mack

Mack
please could you post the code for doing this .

Hi all
No one could help solving this problem?
any suggestion is appreciared

OL,
I thought you were 'on your way' with Mack's offers above.

It's Sunday here, so I take the liberty of some short-cut answer....

I think you'll find 2/3 of a solution in a prior post:
viewtopic.php?t=2844&highlight=random+array (note these keywords... you may find other prior solutions too)
specifically:
Some further ideas:
- if you always place your correct answer as the first or last item in the array, you can manipulate your random-choosing process to select from 'words1.length -1' guided appropriately for beginning subset or ending subset.
- I would find it easy to select 3 random --- and then replace one of those element's value with the '0' or 'last' element (the 'correct one'). The other way Mack suggested was select 2, and then insert or join so as to always include the correct answer value.

I think that covers it, depending how you present or sequence the final 3 possible answers.

Thanks a lot Lar and Mack

I see it's difficult for me to do it that way

i want now to do in other way

1.how can I make sure that an element is exist in the array

2. how to do looping while this array contains this element and stop

I want the code for this thing

I doubt it but hey...

myArray = new Array(1,2,3,4,5,6,7,8,9)
myMatch = 7


1.

if (myArray[0]=myMatch)
{
Debug.trace("possunt quia posse videntur ")
} else
{
Debug.trace("cave canem ")
}

2.

var i =0
while (myArray[i] != myMatch)
{
Debug.trace("facile est inventis addere ")
i++
}

Mack or in Latin, Mack

hi Mack again

Debug.trace("possunt quia posse videntur ")

this Debug needs Debug.translation("Latin To Englsh")
then
var Mackavi=latin.String("possunt quia posse videntur ");

var myArray=Mackavi.split(" ");
myText.ReplaceSelection(myArray[2])
Debug.trace(myArray);

Thank you very much Macavi
I'll try to use your code in my way.

I've tried your code mackavi
for number 1 it doesn't work

your code is

myArray = new Array(1,2)
myMatch = 7


1.

if (myArray[0]=myMatch)
{
Debug.trace("possunt quia posse videntur ")
} else
{
Debug.trace("cave canem ")
}



it'll work by this way:

myArray = new Array(1,2)
myMatch = 7


1.

if (myArray[0]==myMatch)
{
Debug.trace("possunt quia posse videntur ")
} else
{
Debug.trace("cave canem ")
}

I'll try the second one and tell you.

Oh, I don't know - if I run it I get a match every time - which seems good to me

Mack

It ain't broken, if you don't care what it does.

P.S Modified the array contents as I have a vision of some poor person triggering an infinite loop

Mack