Digital Workshop

Hi,

I try to add some variables values with a for loop but don't know exactly how to do this.

I have 18 variables with names like "Question1", "Question2", "Question3" and so on. I would like to add the values of all 18 variables into the variable "Result".


I tried the following:

for (i = 1;18;++)
{Result = Result + (Question&i)
}

But this does not work.

Help is very appreciated.


T.

Try this:

for (i = 1;i<19;++)
{
Result = Result + eval('Question'+i)
}


Didn't test in Opus, but tested in JavaScript, so theoretically it should work.

... unfortunately not. It seems that the for loop is not executed a single time. I put a Debug.trace message into it which is not displayed when I start the loop by mouse click.

Can you do it as a series of actions without scripting? I know it might seem like a lot of effort, but it might actually be easier when all is said and done.

I'm looking for a more elegant way because the number of questions changes often and I thought that this way is easier to work with.

Maybe someone else knows how to do it.


T.

Hi T

I've run into this problem before when i is used previously in the script.
Try this

i=1
for(i=1;i<19;i++)
{
Result = Result+eval("Question"+i)
}

HTH
Chris

... I don't know why but this does not work. I can use Result = Question1 + Question2 + Question3 ... instead. That works. Nevertheless it would be interesting to learn how to do this with a for loop.

Maybe someone of the DW team can help?


T.

Chris has given you the correct answer -- you haven't
initialized the variables, so the loop won't fire.
Try this -- see attached pub.

cheers
Paul

// ########## Script ############

// initialise

var Result=0;

var Question1=10
var Question2=20
var Question3=30
var Question4=40
var Question5=50

for(i=1;i<6;i++)
{
Result = Result + eval("Question"+i)
Debug.trace("Accumulative Result "+i+" = "+Result + "\n"+"\n")
}

Debug.trace("Final Result = "+Result + "\n"+"\n")

// ########### end script ########

Hi Paul,

thank you very much. This works.


T.